A nice math Olympiad problem |you should try to solve this#math #matholympiad

Published 2024-03-01
A nice math algebra simplification | you should know this trick

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All Comments (21)
  • @dneary
    There's a nice way using Viete's formulas - a,b are the roots of the equation x^2-(a+b)x + ab = 0, after finding ab=-1/2 you get 2x^2-2x-1 = 0 or x^(n+2)=x^(n+1) + (x^n)/2 - always true for roots a,b, giving the recursive relationship a^(n+2) + b^(n+2) = (a^(n+1) + b^(n+1)) + (a^n + b^n)/2.
  • @aminimam5118
    b=1-a substitute for b in a^2+b^2=2. You will get 2*a^2-2*a-1=0 you can find a and b
  • @MegaSARITE
    Let a+b =S and ab=P. In the second equation a^2+b^2 =(a+b)^2-2ab=2 leads to ab=-1/2. If a and b are solutions of the quadratic equation X^2+PX+S=0, that give us to a,b =(1±√3)/2.
  • @karolissad.4270
    DUDE YOU NEED TO DRAW 1'S NOT LIKE STICKS CAUSE I THOUGHT YOU WERE TAKING THE DOUBLE DERIVATIVE OF A AND B!!!
  • Let Sn be a^n + b^n Then you can show Sn+1 = Sn + 1/2Sn-1 S11 can be calculated with primary school math starting from S1 and S2
  • another solution: let d = (a+b-1=0), given g= (a^2+b^2-2=0) get remainder g/d = 2*b^2-2*b-1 =0 => b=1/2 +/- sqrt(3)/2. use synthetic division (a^11+b^11)/(a+b-1) and get remainder R(b): R(b)=11*b^10 - 55*b^9 + 165*b^8 - 330*b^7 + 462*b^6 - 462*b^5 + 330*b^4 - 165*b^3 + 55*b^2 - 11*b + 1. now use synthetic division R(b)/(b-(1/2+/-sqrt(3)/2) -> 989/32 => final result (a^11+b^11)=989/32)
  • @johnstanley5692
    alternative? 2*x^2-2*x-1 =0 & x^11+y^11= (2048*x^22-1)/(2048*x^11) . Use synthetic division (by 2*x^2-2*x-1) on both numerator and denominator to obtain remainders. i.e. x^11+y^11 -> (1129438*x+413402)/ (36544*x+13376) = 989/32 .
  • Time taking and lengthy process. If you can find value of a-b by the formula (a-b)^2=(a+b)^2-4ab, after that find the value of a & b , finally you put the value get the answer
  • @n.662
    Music no need for this video. You can say) . Think you!
  • @dailang2144
    smart way but ... too "dump". Easy to find a, b => done :-)
  • @rajurkarj
    Perfect solution..👍. Here there is no other shortcut trick.. What is the point to find value of a and b?
  • @prime423
    You could use the a to the fifth equation to the same benefit.
  • @Ramyleithy
    ليه المرار الطافح ده ، استخدم نظرية ذات الحدين واخلص
  • I am always puzzled when I see solutions like that. Who the hell need it? You have two equations with two variables. Easily find both of them as (1+=sqrt(3)/2 and after any of their combination. How twisted mind should people have to post 16 minutes video with crazy computations for that task?